Having explained the motion of the dials by which the addition,
excluding the carriages of the number on the row D^1, may be made to the
number on the row T, the same explanation may be applied to the number
on the row D^2 to the number on the row D^1; also, of the number D^3 to the
number on the row D^2, and so on. Now it is possible to suppose the
additions of all the rows, except the first, to be made to all the rows
except the last, simultaneously; and after these additions have been
made, to conceive all the requisite carriages to be also made by
advancing the proper dials one division forward. This would suppose all
the dials in the scheme to receive their adding motion together; and,
this being accomplished, the requisite dials to receive their carrying
motions together. The production of so great a number of simultaneous
motions throughout any machinery, would be attended with great
mechanical difficulties, if indeed it be practicable. In the calculating
machinery it is not attempted. The additions are performed in two
successive periods of time, and the carriages in two other periods of
time, in the following manner. We shall suppose one complete revolution
of the axis which moves the machinery, to make one complete set of
additions and carriages; it will then make them in the following
order:--
The first quarter of a turn of the axis will add the second, fourth, and
sixth rows to the first, third, and fifth, omitting the carriages; this
it will do by causing the dials on the first, third, and fifth rows, to
turn through as many divisions as are expressed by the numbers at the
indices below them, as already explained.
The second quarter of a turn will cause the carriages consequent on the
previous addition, to be made by moving forward the proper dials one
division.
(During these two quarters of a turn, the dials of the first, third, and
fifth row alone have been moved; those of the second, fourth, and sixth,
have been quiescent.)
The third quarter of a turn will produce the addition of the third and
fifth rows to the second and fourth, omitting the carriages; which it
will do by causing the dials of the second and fourth rows to turn
through as many divisions as are expressed by the numbers at the indices
immediately below them.
The fourth and last quarter of a turn will cause the carriages
consequent on the previous addition, to be made by moving the proper
dials forward one division.
This evidently completes one calculation, since all the rows except the
first have been respectively added to all the rows except the last.
Public-domain text, read in full here on John Shaqi.
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