From these equations, it appears that for an observer, which moves with
the velocity c towards the source of light, the source should appear
infinitely intense.
§ 8. Transformation of the Energy of the Rays of Light. Theory of the
Radiation-pressure on a perfect mirror.
Since A²/8π is equal to the energy of light per unit volume, we have to
regard A²/8π as the energy of light in the moving system. A′²/A² would
therefore denote the ratio between the energies of a definite
light-complex “measured when moving” and “measured when stationary,” the
volumes of the light-complex measured in K and _k_ being equal. Yet this
is not the case. If _l_, _m_, _n_ are the direction-cosines of the
wave-normal of light in the stationary system, then no energy passes
through the surface elements of the spherical surface
(_x_ - _clt_)² + (_y_ - _cmt_)² + (_z_ - _cnt_)² = R²,
which expands with the velocity of light. We can therefore say, that
this surface always encloses the same light-complex. Let us now consider
the quantity of energy, which this surface encloses, when regarded from
the system _k_, _i.e._, the energy of the light-complex relative to the
system _k_.
Regarded from the moving system, the spherical surface becomes an
ellipsoidal surface, having, at the time τ = 0, the equation:—
$$ (\beta \xi - l \beta \frac {v}{c} \xi)^2 + (\eta - m \beta \frac
{v}{c} \xi)^2 + (\zeta - n \beta \frac {v}{c} \xi)^2 = R^2 $$
If S = volume of the sphere, S′ = volume of this ellipsoid, then a
simple calculation shows that:
$$ \frac {S'}{S} = \frac {\beta}{\sqrt{1 - \frac {v}{c} \cos \Phi}} $$
If E denotes the quantity of light energy measured in the stationary
system, E′ the quantity measured in the moving system, which are
enclosed by the surfaces mentioned above, then
$$ \frac {E'}{E} = \frac {\frac {A'^2}{8\pi} S'}{\frac {A^2}{8\pi}S} =
\frac {1 - \frac {v}{c} \cos \Phi}{\sqrt{1 - \frac {v^2}{c^2}}} $$
If Φ = 0, we have the simple formula:—
$$ \frac {E'}{E} = (\frac{1 - \frac{v}{c}}{1 +
\frac{v}{c}})^{\frac{1}{2}} $$
It is to be noticed that the energy and the frequency of a light-complex
vary according to the same law with the state of motion of the observer.
Let there be a perfectly reflecting mirror at the co-ordinate-plane ξ =
0, from which the plane-wave considered in the last paragraph is
reflected. Let us now ask ourselves about the light-pressure exerted on
the reflecting surface and the direction, frequency, intensity of the
light after reflexion.
Let the incident light be defined by the magnitudes A cos Φ, _v_
(referred to the system K). Regarded from _k_, we have the corresponding
magnitudes:
$$ A' = A \frac{1 - \frac{v}{c} \cos \Phi}{\sqrt{1 - \frac{v^2}{c^2}}}
$$
$$ \cos \Phi' = \frac{\cos \Phi - \frac{v}{c}}{1 - \frac{v}{c} \cos
\Phi} $$
$$ \nu' = \nu \frac{1 - \frac{v}{c} \cos \Phi}{\sqrt{1 -
\frac{v^2}{c^2}}} $$
For the reflected light we obtain, when the process is referred to the
system _k_:—
Public-domain text, read in full here on John Shaqi.
Reviews
Reviews
No reviews yet
Be the first to share your thoughts on this work.
Join the Discussion
Join the discussion
Sign in to leave a comment or review.
Sign InorCreate an account