The Sewerage of Sea Coast TownsAdams, Henry Charles
Science
The Sewerage of Sea Coast Towns
Adams, Henry Charles
Sewerage
Triangular or V notches are usually formed so that the angle
between the two sides is 90°, when the breadth at any point
will always be twice the vertical height measured at the
centre. The discharge in this case varies as the square root of
the fifth power of the height instead of the third power as
with the rectangular notch. The reason for the alteration of
the power is that _approximately_ the discharge over a notch
with any given head varies as the cross-sectional area of the
body of water passing over it. The area of the 90° notch is
half that of a circumscribing rectangular notch, so that the
discharge of a V notch is approximately equal to that of a
rectangular notch having a width equal to half the width of the
V notch at water level, and as the total width is equal to
double the depth of water passing over the notch the half width
is equal to the full depth and the discharge is equal to that
of a rectangular notch having a width equal to the depth of
water flowing over the V notch from time to time, both being
measured in the same unit, therefore
____ ____ ____
C \/ H^3 becomes C x H x \/ H^3 which equals C \/ H^5.
The constant C will, however, vary from that for the
rectangular notch to give an accurate result.
TABLE No. 6.
TRIANGULAR OR V NOTCHES.
____
Discharge = C x \/ H^5.
Values of C.
--------------+-----------------------+------------------------
H Measured in | Feet. | Inches.
--------------+----------+------------+-----------+------------
Discharge in | Gallons | C. ft per | Gallons | C. ft per
| per hour | min | per hour. | min
--------------+----------+------------+-----------+------------
Alexander | 59,856 | 160 | 120.0 | 0.321
Cotterill | 57,013 | 152.4 | 114.3 | 0.306
Molesworth | 59,201 | 158.2 | 118.7 | 0.317
Thomson | 57,166 | 152.8 | 114.6 | 0.306
--------------+----------+------------+-----------+------------
Cotterill's formula for the discharge in cubic feet per minute
is
_______
16 x C x B \/ 2g H^3
when B = breadth of notch in feet and H = height of water in
feet and can be applied to any proportion of notch. When B =
2H, that is, a 90° notch, C = .595 and the formula becomes
____
152.4 \/ H^5,
and when B = 4H, that is, a notch containing an angle of 126°
51' 36", C = .62 and the formula is then written
____
318 \/ H^5.
Public-domain text, read in full here on John Shaqi.
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