The slide rule : $b a practical manualPickworth, Charles N. (Charles Newton)
Science
The slide rule : $b a practical manual
Pickworth, Charles N. (Charles Newton)
Slide-rule
Set 4·5 on C to 0·294 on D, and over 0·625 on D read 9·56 lb. per
lineal foot on C.
To find the weight per square foot of sheet metal, set the weight per
cubic foot of the metal (col. 1) on C to 12 on D, and
────────────┬──────────┬──────────┬──────────┬───────────
│ (1) │(2) │ (3) │ (4)
│Weight in │Weight of │ (1)/(Wt. │ Weight of
Metals. │ lb. per │12 cubic │of 12 cub.│ 12
│cubic ft. │in. │ in.) │cylindrical
│ │ │ │ in.
────────────┼──────────┼──────────┼──────────┼───────────
Wrought iron│480 │3·33 │0·300 │2·62
Cast iron │450 │3·125 │0·320 │2·45
Cast steel │490 │3·40 │0·294 │2·68
Copper │550 │3·82 │0·262 │3·00
Aluminium │168 │1·166 │0·085 │0·915
Brass │520 │3·61 │0·277 │2·83
Lead │710 │4·93 │0·203 │3·87
Tin │462 │3·21 │0·312 │2·52
Zinc (cast) │430 │2·98 │0·335 │2·34
„ (sheet) │450 │3·125 │0·320 │2·45
────────────┴──────────┴──────────┴──────────┴───────────
above the thickness of the plate in inches on D read weight in lb. per
square foot on C.
EX.—Find the weight in lb. per square foot of aluminium sheet ⅜in.
thick.
Set 168 on C to 12 on D, and over 0·375 on D read 5·25 lb. on C.
To find the weight of pipes in lb. per lineal foot.
Set mean diameter of the pipe in inches (_i.e._, internal diameter
_plus_ the thickness, or external diameter _minus_ the thickness) on C
to the constant given below on D, and over the thickness on D read
weight in lb. per lineal foot on C.
┌────────────┬─────────────────────┬─────────────────────┐
│ Metals. │ Constant for Pipes. │Constant for Spheres.│
├────────────┼─────────────────────┼─────────────────────┤
│Wrought iron│ 0·0955 │ 6·87 │
│Cast iron │ 0·1020 │ 7·35 │
│Steel │ 0·0936 │ 6·73 │
│Brass │ 0·0882 │ 6·35 │
│Copper │ 0·0834 │ 6·00 │
│Lead │ 0·0646 │ 4·65 │
└────────────┴─────────────────────┴─────────────────────┘
EX.—Find the weight per foot of cast-iron piping 4 in. internal
diameter and ½in. thick.
Set 4·5 on C to 0·102 on D, and over 0·5 on D read 22·1 lb. on C, the
required weight.
To find the weight in lb. of spheres or balls, given the diameter in
inches. (W = 0·5236_d_^3 × wt. of 1 cub. in. of material).
Set the constant for spheres (given above) on B to diameter in inches on
A, and over diameter on C read weight in lb. on A.
Public-domain text, read in full here on John Shaqi.
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