The Solution of the Pyramid Problem; or, Pyramid Discoveries: With a New Theory as to their Ancient UseBallard, Robert
History
The Solution of the Pyramid Problem; or, Pyramid Discoveries: With a New Theory as to their Ancient Use
Ballard, Robert
Pyramids
I firmly believe that so far as I have gone it is correct--and it is
possible, therefore, with the start that I have made, for others to
continue the work, and add the eleven pyramids to the plan in their
correct geometrical position. By continuing the system of evolution by
which I defined the position of Cephren, and the little pyramid to the
south-east of Cheops, after I had obtained Cheops and Mycerinus, may be
rebuilt, at one and the same time, a skeleton of the trigonometrical
tables of a forgotten civilization, and the plan of those pyramids which
are its only link with the present age.
§ 13. THE SIZE AND SHAPE OF THE PYRAMIDS INDICATED BY THE PLAN.
I pursued my investigations into the slopes and altitudes of the
pyramids without reference to the plan, after once deciding their exact
bases.
Now it will be interesting to note some of the ways in which the plan
hints at the shape and size of these pyramids, and corroborates my work.
The dimensions of _Cheops_ are indicated on the plan by the lines EA to
YA, measuring 840 and 288 R.B. cubits respectively, being the half
periphery of its horizontal section at the level of Cephren's base, and
its own altitude from its own base. (_See Fig_. 5.)
The line EA, in fact, represents in R.B. cubits the half periphery of
the bases of either Cheops or Cephren measured at the level which I
have set forth as the _plan level_, viz., base of Cephren.
The ratio of Cephren's base to Cephren's altitude is indicated on the
plan by the ratios of the lines BC to EB, or FO to OR, viz., 32 to 21.
(_See Fig._ 4.)
The altitude of Mycerinus above Cephren's base appears on plan in the
line EF, measuring 136 R.B. cubits.
The line EO on plan measures 888 cubits, which would be the length of a
line stretched from the apex of Cheops to the point E, at the level of
Cheops' base.
This merits consideration:--the lines EA and AY are connected on plan at
the centre of Cheops, and the lines EO and EA are connected on plan at
the point E.
Now the lines EO, EA and AY are sides of a "primary triangle," whose
ratio is 37, 35, 12, and whose measure in cubits is 888, 840, and 288;
and if we suppose the line EA to be stretched horizontally beneath the
pyramids at the level of the base of Cheops from E to A on plan, and the
line AY to be a plumb line hanging from the apex of Cheops to the level
of his base, then will the line EO just stretch from the point E to the
apex of Cheops, and the three lines will connect the two main pyramids
by a vertical triangle of which EA, AY and EO form the base,
perpendicular, and hypotenuse. Or, to explain it in another manner: let
the line EA be a _cord_ stretching horizontally from A at the centre of
the base of Cheops to the point E, both ends being at the same level;
let the line AY be a _rod_, lift it on the end A till it stands erect,
then is the end Y the apex of Cheops. Now, the line EO would just
stretch from the top of the rod AY to the point E first described.
Public-domain text, read in full here on John Shaqi.
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