The Steam Engine Familiarly Explained and Illustrated: With an historical sketch of its invention and progressive improvement; its applications to navigation and railways; with plain axioms for railway speculatorsLardner, Dionysius
History
The Steam Engine Familiarly Explained and Illustrated: With an historical sketch of its invention and progressive improvement; its applications to navigation and railways; with plain axioms for railway speculators
Lardner, Dionysius
Steam-engines -- Early works to 1850
In a double-acting engine, in good working condition, the total power
of steam in the boiler being expressed by 1000, the proportion
intercepted by the engine, exclusive of the resistance of the
uncondensed steam, will be 368, and the effective part 632. Now,
suppose the pressure of steam in the boiler to be measured by a column
of 35 inches of mercury; the thousandth part of this will be seven two
hundredths of an inch of mercury, and 632 of these parts will express
the effective portion of the power. By multiplying seven two
hundredths by 632, we obtain 22 nearly. Now, suppose the temperature
in the condenser is 1200, the pressure of steam corresponding to that
temperature will be measured by 3-7/10 inches of mercury. Subtracting
this from 22, there will remain 18-3/10 inches of mercury, as the
effective moving force upon the piston; this will be equivalent to
about 7 lbs. on each circular inch.
If the diameter of the piston then be 24 inches, its surface will
consist of a number of circular inches expressed by the square of 24,
or 24 × 24 = 576; and, as upon each of these circular inches there is
an effective pressure of 7 lbs., we shall find the total pressure in
pounds by multiplying 576 by 7, which gives 4032 lbs.
We shall find the space through which this force works per minute, by
knowing the length of the cylinder and the number of strokes per
minute. Suppose the length of the cylinder to be 5 feet, and the
number of strokes per minute 21-1/2. In each stroke[51] the piston
will, therefore, move through 10 feet, and in one minute it will move
through 215 feet. The moving force, therefore, is 4032 lbs. moved
through 215 feet per minute, which is equivalent to 215 times 4032
lbs., or 866,880 lbs., raised one foot per minute.
[Footnote 51: By a stroke of the piston is meant its motion from one
end of the cylinder and back again.]
For every 33,000 lbs. contained in this, the engine has a horse-power.
To find the horse-power, then, of the engine, we have only to divide
866,880 by 33,000; the quotient is 26 nearly, and, therefore, the
engine is one of 26 horse power.
Let it be required to determine the quantity of water which a boiler
must evaporate per hour, for each horse-power of the engine which it
works.
Public-domain text, read in full here on John Shaqi.
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