Time and Clocks: A Description of Ancient and Modern Methods of Measuring Time — John Shaqi
Time and Clocks: A Description of Ancient and Modern Methods of Measuring TimeCunynghame, Henry H. (Henry Hardinge), Sir
Philosophy
Time and Clocks: A Description of Ancient and Modern Methods of Measuring Time
Cunynghame, Henry H. (Henry Hardinge), Sir
Clocks and watches; Time
From this, then, it follows that if a _force_ continues to act on a
body the body keeps moving quicker and quicker. When the force stops
acting, the motion already acquired goes on, but the acceleration
stops. That is to say, the body goes on moving in a straight line
uniformly at the pace it had when the force stopped.
If, then, a body is exposed to the action of a force, and held tight,
what will happen? It will, of course, remain fixed. Now let it go—it
will then, being a free body, begin to move. As long as the force
acts, the force keeps putting more and more motion into the body, like
pouring water into a jug, the longer you pour the faster the motion
becomes. The body keeps all the motion it had, and keeps adding all the
motion it gains. It is like a boy saving up his weekly pocket-money:
he has what he had, and he keeps adding to that. So if in one second
a motion is imparted of one foot a second, then in another second a
motion of one foot a second more will be added, making together a
motion of two feet a second; in another second of force action the
motion will have been increased or “accelerated” by another foot per
second, and so on. The speed will thus be always proportional to
the force and the time. If we write the letter V to represent the
motion, or speed, or velocity; F to represent the acceleration or gain
of motion; and T to represent the time, then V = FT. Here V is the
velocity the body will have acquired at the end of the time T, if free
to move and submitted to a force capable of producing an acceleration
of F feet per second in a unit of time.
V is the final velocity. The average velocity will be 1/2 V, for it
began with no velocity and increased uniformly. How far will the body
have fallen in the interval? Manifestly we get that by multiplying the
time by the average velocity, that is S = 1/2 VT, where V, as I said,
is the final velocity, but we found that V = FT. Hence by substitution
S = 1/2 FT × T = 1/2 FT².
It is to be carefully borne in mind that these letters V, S, and T
do not represent velocities, spaces, and times, but merely represent
arithmetical numbers of units of velocities, spaces, and times. Thus
V represents V feet per second, S represents S feet, and T represents
T seconds. And when we use the equation V = FT we do not mean that
by multiplying a force by a time you can produce a velocity. If, for
instance, it be true that you can obtain the number of inhabitants (H)
in London by multiplying the average number of persons (P) who live
in a house by the number of houses (N), this may be expressed by the
equation H = PN. But this does not mean that by multiplying people into
houses you can produce inhabitants. H, P, and N are numbers of units,
and they are _numbers only_.
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