The English works of Thomas Hobbes of Malmesbury, Volume 01 (of 11)
Thomas Hobbes · en
| 1 | 2 3 4 5 6 7
Parallelogram | 1 | : : : : : :
+----+
Strait-sided triangle | 1/2| : : : : : :
|----+
Three-sided figure of 1 mean | 2/3| : : : : : :
|----+----+
Three-sided figure of 2 means | 3/4| 3/5| : : : : :
|----+----+----+
Three-sided figure of 3 means | 4/5| 4/6| 4/7| : : : :
|----+----+----+----+
Three-sided figure of 4 means | 5/6| 5/7| 5/8|5/9 | : : :
|----+----+----+----+----+
Three-sided figure of 5 means | 6/7| 6/8| 6/9|6/10|6/11| : :
|----+----+----+----+----+----+
Three-sided figure of 6 means | 7/8| 7/9|7/11|7/11|7/12|7/13| `` :
|----+----+----+----+----+----+----+
Three-sided figure of 7 means | 8/9|8/10|8/11|8/12|8/13|8/14|8/15|
+----+----+----+----+----+----+----+
[Sidenote: Description & production of the same figures.]
4. Now for the better understanding of the nature of these three-sided
figures, I will show how they may be described by points; and first,
those which are in the first column of the table. Any parallelogram
being described, as A B C D (in figure 2) let the diagonal B D be drawn;
and the strait-lined triangle B C D will be half the parallelogram; then
let any number of lines, as E F, be drawn parallel to the side B C, and
cutting the diagonal B D in G; and let it be everywhere, as E F to E G,
so E G to another, E H; and through all the points H let the line B H H
D be drawn; and the figure B H H D C will be that which I call a
three-sided figure of one mean, because in three proportionals, as E F,
E G and E H, there is but one mean, namely, E G; and this three-sided
figure will be 2⁄3 of the parallelogram, and is called a _parabola_.
Again, let it be as E G to E H, so E H to another, E I, and let the line
B I I D be drawn, making the three-sided figure B I I D C; and this will
be 3⁄4 of the parallelogram, and is by many called a _cubic parabola_.
In like manner, if the proportions be further continued in E F, there
will be made the rest of the three-sided figures of the first column;
which I thus demonstrate. Let there be drawn strait lines, as H K and G
L, parallel to the base D C. Seeing therefore the proportion of E F to E
H is duplicate to that of E F to E G, or of B C to B L, that is, of C D
to L G, or of K M (producing K H to A D in M) to K H, the proportion of
B C to B K will be duplicate to that of K M to K H; but as B C is to B
K, so is D C or K M to K N, and therefore the proportion of K M to K N
is duplicate to that of K M to K H; and so it will be wheresoever the
parallel K M be placed. Wherefore the figure B H H D C is double to its