The philosophical and mathematical commentaries of Proclus on the first book of Euclid's elements (Vol. 1 of 2) : $b To which are added, A history of the restoration of Platonic theology, by the latter Platonists: And a translation from the Greek of Proclus's Theological elements — Plato — John Shaqi
The philosophical and mathematical commentaries of Proclus on the first book of Euclid's elements (Vol. 1 of 2) : $b To which are added, A history of the restoration of Platonic theology, by the latter Platonists: And a translation from the Greek of Proclus's Theological elements
Plato · en
simplicity of the impulsive motion, such a line must either be straight
or circular; for there are only three lines every where similar, i. e.
the right and circular line, and the cylindric helix; but this last,
as Proclus well observes in his following Commentary on the fourth
definition, is not a simple line, because it is generated by two simple
motions, the rectilineal and circular. But the line which bounds more
than two equal tangent arches cannot be a right line, as is well known
to all geometricians; it is therefore a circular line. It is likewise
evident, that this arch _o x_ is concave towards the point _g_: for if
not, it would pass beyond the chord _o x_, which is absurd. And again,
no arch greater than the quadrant can be unbent by this motion: for any
one of the radii, as _a p_ beyond _g o_, has a tendency from, and not
to the tangent _g x_, which last is necessary to our hypothesis. Now if
we conceive another quadrantal arch of the circle _g o e f_, that is
_g y_, touching the former in _g_ to be unbent in the same manner, the
arch _x y_ shall be a continuation of the arch _x o_; for if _γ x κ_ be
drawn perpendicular to _x g_, as in the figure, it shall be a tangent
in _x_ to the equal arches _y x_, _x o_; because it cannot fall within
either, without making the sine of some one of the equal arches, equal
to the right-line _x g_, which would be absurd. And hence we may easily
infer, that the centre of the arch _y x o_, is in the tangent line _x
g_. Hence too, we have an easy method of finding a tangent right-line
equal to a quadrantal arch: for having the points _y_, _o_ given, it is
easy to find a third point, as _s_; and then the circle passing through
the three points _o_, _s_, _y_, shall cut off the tangent _x g_,
equal to the quadrantal arch _g o_. And the point _s_ may be speedily
obtained, by describing the arch _g s_ with a radius, having to the
radius _a g_ the proportion of 6 to 4; for then _g s_ is the sixth part
of its whole circle, and is equal to the arch _g o_. And thus, from
this hypothesis, which, I presume, may be as readily admitted as the
increments and decrements of lines in fluxions, the quadrature of the
circle may be geometrically obtained; for this is easily found, when a
right-line is discovered equal to the periphery of a circle. I am well
aware the algebraists will consider it as useless, because it cannot be
accommodated to the farrago of an arithmetical calculation; but I hope
the lovers of the ancient geometry will deem it deserving an accurate
investigation; and if they can find no paralogism in the reasoning,
will consider it as a legitimate demonstration.
[Illustration]
[Illustration]