A new system of chemical philosophy, Volume 2, Part 1 — John Shaqi
A new system of chemical philosophy, Volume 2, Part 1Dalton, John
Science
A new system of chemical philosophy, Volume 2, Part 1
Dalton, John
Atomic theory; Chemistry, Inorganic
One fact has been for some time known which demonstrates the oxygen in
the red oxide to be double that in the black. Corrosive sublimate may
be reduced to calomel by adding to it as much mercury as the sublimate
contains, and triturating the mixture well, the oxygen of the red oxide
(as well as the acid) becomes equally divided amongst the mercury and
forms the black oxide, which is a constituent of calomel. Hence it
follows that if the oxygen in one oxide can be ascertained, that of the
other becomes known. Or if we can find how much oxygen must be added
to the black oxide to change it to the red, we shall know the oxygen
in both. Conformably with this last idea I have found a very accurate
and elegant method of ascertaining the oxygen required to convert the
black to the red oxide by treating protomuriate of mercury, mixed with
water and a little muriatic acid, with oxymuriate of lime in solution;
this must be gradually added till the protomuriate is dissolved, or
rather converted to the deutomuriate. The quantity of oxygen in a given
solution of oxymuriate of lime is most conveniently found by a solution
of green sulphate of iron, as will be shewn under the oxides of that
metal.
The oxides of mercury may be investigated by the nitrous gas produced
during solution. When mercury is dissolved without heat, as mentioned
above, no nitrous gas is liberated. The solution has a strong nitrous
smell and requires a great quantity of oxymuriate of lime to saturate
both the oxide and the acid. When heat is employed to accelerate the
solution, nitrous gas is liberated. I dissolved 154 grains of mercury
in nitric acid, 1.2 sp. gr., by the application of a gentle heat from
a lamp. About ⅒ excess of acid remained in the solution; the nitrous
gas obtained was 12 oz. measures = 7.5 grains, corresponding to 6.5
oxygen, which gives nearly 4 oxygen or 100 mercury. This would have
led me to suppose I had obtained the _black_ oxide in solution; it was
however entirely the _red_, as it gave no precipitate by common salt,
and exhibited the red oxide by lime water; but it required as much
oxymuriate of lime as contained 6.5 oxygen to saturate the _nitrous
gas_ in the solution before any oxymuriatic acid was liberated. It was
clear therefore that only ½ of the nitrous gas was evolved, and the
other ½ was retained in the solution, though it had been exposed to
boiling heat.
The following are the proportions assigned by the several authors for
the oxides of mercury.
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