Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.Baldwin, Thomas
History
Airopaidia : $b Containing the narrative of a balloon excursion from Chester, the eighth of September, 1785, taken from minutes made during the voyage; hints on the improvement of balloons ... To which is subjoined, mensuration of heights by the barometer, made plain; with extensive tables. The whole serving as an introduction to aërial navigation.
Baldwin, Thomas
Aeronautics -- Early works to 1900; Balloons -- Early works to 1800
395. To find the Expansion of .6 above 4° on .178 above 24 Inches.
The Expansion _with_ 4° _on_ .178 is already found to be .0000712:
divide it by 4, and the Answer is .0000178, viz. the Expansion _with_
1° _on_ .178 above 24 Inches:
And, for the Expansion with .1 Tenth; the Answer, with the Addition of
a Cypher and decimal Point to the left, becomes .00000178.
Lastly, for the Expansion with .6, say,
If .1 : .00000178 :: .6?
Multiply the 2d and 3d Terms, and divide by first:
.00000178
.6
——————————
.000001068.
The Answer is a Decimal less, viz. .00001068; i.e. the Decimal of an
Inch, to which .6 Tenths of a Degree above 4 Degrees of Heat, on .178
Tenths of an Inch above 24 Inches, raises the Barometer: which, after
all, is so inconsiderable, that it may be fairly rejected.
Yet the Rules by which these Deductions are made, may be useful in
other Cases.
Prepare for Addition, as before.
The Decimals, in the Answers, may be omitted, when they exceed four
Places.
[Sidenote: 5th Step.]
396. 5th Step. To proceed with the second Example.
Place the different Expansions now found, above each other, Units,
Tens, &c. under Units, Tens, &c. preparatory to Addition, thus;
For the Expansion _with_ 4°, .6 _on_ 24, .178:
1st. _with_ 4°, _on_ 24, .0097
2d. _with_ .6 _on_ 24, .00144
3d. _with_ 4°, _on_ .178 .0000712
4th. _with_ .6 _on_ .178 .00001068
—————————
The Expansions with 4°,.6 added = .01122188
To the Sum add the Height of
the _colder_ Barometer 24.178
———————————
24.1892|
The Answer is Height of the _colder_ Barometer, now equal in
Temperature to the _warmer_: (rejecting all but the four first
Decimals.)
[Sidenote: 6th Step.]
397. 6th Step. Place the Barometers _now_ of the same Temperature, i.e.
_equal_ to the warmer, in one View, thus:
1st. the _upper_ Barometer, 24.1892
2d. the _lower_ Barometer, 28.1328
END OF THE FIRST STAGE.
_The 7th Step applied in the second Example._
[Sidenote: _7th Step._]
398. Find the Height, in Feet, in the 2d Column of the 2d Table,
corresponding to Inches and Tenths of the _upper_ barometric Tube, in
the 1st. Column of the same Table, thus: (Sect. 371.)
The Barometer standing at 24.1892; it must be considered where, in the
2d Column of the 2d Table, a Height corresponding to _such_ Inches
and Tenths can lie: and the Answer is, somewhere _above_ 24 Inches .1
Tenth, but not so high as 24 Inches .2 Tenths: 24 Inches .1892 Tenths,
being _more_ than 24 Inches .1 Tenth, but _less_ than 24 Inches .2
Tenths.
First then, look in the 1st Column for Inches 24, .1 Tenth; and the
corresponding Height in Feet is 7388.0: but the Height for 24, .2, in
the 2d Column, beneath the former Number, is _only_ 7280.1.
[Sidenote: 8th Step.]
Public-domain text, read in full here on John Shaqi.
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