, fall outside the Triangle ;
Triangle is greater than Triangle .
Therefore, if two isosceles Triangles &c.
Q.E.D.
[Pg 6]
PROP. III. Problem.
Given a certain angle; and given that any isosceles Triangle, whose
vertical angle is not-greater than the given angle, has its base
not-greater than either of its sides: to describe, on a given base, an
isosceles Triangle having each base-angle equal to the given angle.
Let be given base.
At , in Line , make angle equal to given angle,
making ; and join .
Then, by hypothesis, is not-greater than : i. e. it is
either equal to it, or less than it.
First let be equal to . (Fig. 1.)
Then Triangle is equilateral: i. e. it is an isosceles
Triangle, on given base , and having each base-angle equal to
given angle.
Q.E.F.
Secondly, let be less than . (Fig. 2.)
Then angle is less than angle .
[Euc. I. 18.
At make angle equal to angle .
[Euc. I. 23.
Then Triangle is isosceles, and is on given base , and
has each base-angle equal to given angle.
Q.E.F.
[Pg 7]
Corollary.
The isosceles Triangle, so described, has its vertical angle
not-less than either of its base-angles.
For, in Fig. 1, ;
.
Q.E.D.
Again, in Fig. 2, ;
.
But angle is greater than angle ;
[Euc. I. 16.
and angle is less than angle ;
.
Q.E.D.
[Pg 8]
PROP. IV. Theorem.
Either all Triangles have the same 'amount'; or else, if ,
be two 'possible amounts,' that is, 'amounts' belonging to
existing Triangles, then any 'amount,' intermediate to and
, is also 'possible.'
If all Triangles have the same amount, the Proposition is true. If not,
let , be two Triangles whose amounts are different. Call
their 'amounts' ', .' And let the two Triangles be
placed so as to have a common vertex at , and their bases in the
same straight Line.
Now Triangle may be converted into Triangle by making
the point, where intersects , move from to ,
remaining stationary.
And, during this process, the angle at will vary continuously,
[Ax. 4.
and the angle, at the point where the revolving Line intersects ,
will vary continuously;
[Ax. 5.
the sum of these angles will, if it vary at all, vary
continuously.
[Ax. 3.
Similarly, Triangle may be converted, first, into Triangle
, by making the point, where intersects , move from
to , remaining stationary, and then into Triangle
, by making the point, where intersects , move from
to , remaining stationary.
And, during the whole process, the 'amount' of the changing Triangle
will, if it vary at all, vary continuously.
Hence, in changing from the value to the value , it
must pass through all intermediate 'amounts': i. e. all intermediate
'amounts' are 'possible.'
[Ax. 2.
Therefore either all Triangles have &c.
Q.E.D.
Corollaries.
[Pg 9]
1.
Among angular magnitudes there is one, and only one, 'possible
region.'
2.
Public-domain text, read in full here on John Shaqi.
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