Suppose that in commencing to observe at a station the error of the
chronometer is not known; then having secured for the instrument a
very solid foundation, removed as far as possible level and
collimation errors, and placed it by estimation nearly in the
meridian, let two stars differing considerably in declination be
observed--the instrument not being reversed between them. From these
two stars, neither of which should be a close circumpolar star, a good
approximation to the chronometer error can be obtained; thus let
[epsilon]1, [epsilon]2, be the apparent clock errors given by these
stars if [delta]1, [delta]2 be their declinations the real error is
[epsilon] = [epsilon]1 + ([epsilon]1 - [epsilon]2)
(tan [phi] - tan [delta]1) / (tan [delta]1 - tan [delta]2).
Of course this is still only approximate, but it will enable the
observer (who by the help of a table of natural tangents can compute
[epsilon] in a few minutes) to find the meridian by placing at the
proper time, which he now knows approximately, the centre wire of his
instrument on the first star that passes--not near the zenith.
The transit instrument is always reversed at least once in the course
of an evening's observing, the level being frequently read and
recorded. It is necessary in most instruments to add a correction for
the difference in size of the pivots.
The transit instrument is also used in the prime vertical for the
determination of latitudes. In the preceding figure let q be the point
in which the northern extremity of the axis of the instrument produced
meets the celestial sphere. Let nZq be the azimuthal deviation = a,
and b being the level error, Zq = 90 deg. - b; let also nPq = [tau]
and Pq = [psi]. Let S' be the position of a star when observed on a
wire whose distance from the collimation centre is c, positive when to
the south, and let h be the observed hour angle of the star, viz.
ZPS'. Then the triangles qPS', gPZ give
-Sin c = sin [delta] cos [psi] - cos [delta] sin [psi] cos (h + [tau]),
Cos [psi] = sin b sin [phi] + cos b cos [phi] cos a,
Sin [psi] sin [tau] = cos b sin a.
Now when a and b are very small, we see from the last two equations
that [psi] = [phi] - b, a = [tau] sin [psi], and if we calculate
[phi]' by the formula cot [phi]' = cot [delta] cos h, the first
equation leads us to this result--
[phi] = [phi]' + (a sin z + b cos z + c)/cos z,
the correction for instrumental error being very similar to that
applied to the observed time of transit in the case of meridian
observations. When a is not very small and z is small, the formulae
required are more complicated.
[Illustration: FIG. 4.--Zenith Telescope constructed for the
International Stations at Mizusawa, Carloforte, Gaithersburg and
Ukiah, by Hermann Wanschaff, Berlin.]
Public-domain text, read in full here on John Shaqi.
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