Mathematical Problems : $b Lecture delivered before the International Congress of Mathematicians at Paris in 1900Hilbert, David
Science
Mathematical Problems : $b Lecture delivered before the International Congress of Mathematicians at Paris in 1900
Hilbert, David
Mathematics
But above all I wish to designate the following as the most important
among the numerous questions which can be asked with regard to the
axioms: To prove that they are not contradictory, that is, that
a finite number of logical steps based upon them can never lead to
contradictory results.
In geometry, the proof of the compatibility of the axioms can be
effected by constructing a suitable field of numbers, such that
analogous relations between the numbers of this field correspond to
the geometrical axioms. Any contradiction in the deductions from the
geometrical axioms must thereupon be recognizable in the arithmetic
of this field of numbers. In this way the desired proof for the
compatibility of the geometrical axioms is made to depend upon the
theorem of the compatibility of the arithmetical axioms.
On the other hand a direct method is needed for the proof of the
compatibility of the arithmetical axioms. The axioms of arithmetic are
essentially nothing else than the known rules of calculation, with the
addition of the axiom of continuity. I recently collected them[4] and
in so doing replaced the axiom of continuity by two simpler axioms,
[Pg 12]
namely, the well-known axiom of Archimedes, and a new axiom essentially
as follows: that numbers form a system of things which is capable of
no further extension, as long as all the other axioms hold (axiom of
completeness). I am convinced that it must be possible to find a direct
proof for the compatibility of the arithmetical axioms, by means of
a careful study and suitable modification of the known methods of
reasoning in the theory of irrational numbers.
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