Suppose that the ions are produced at a constant rate _q_ per cubic
centimetre per second in the gas between parallel plates distant _l_
cms. from each other. When no electric field is applied, the number _N_
present per c.c., when there is equilibrium between the rates of
production and recombination, is given by _q_ = α_N_², where α is a
constant.
If a small potential difference _V_ is applied, which gives only a small
fraction of the maximum current, and consequently has not much effect on
the value of _N_, the current _i_ per sq. cm. of the plate, is given by
_NeuV_
_i_ = -----
_l_
where _u_ is the sum of the velocity of the ions for unit potential
gradient, and _e_ is the charge carried by an ion.
_uV_
----
_l_
is the velocity of the ions in the electric field of strength
_V_
---
_l_
The number of ions produced per second in a prism of length _l_ and unit
area of cross-section is _ql_. The maximum or saturation current _I_ per
sq. cm. of the plate is obtained when all of these ions are removed to
the electrodes before any recombination has occurred.
Thus
_I_ = _q . l . e_,
and
$$ \frac{i}{I} = \frac{NuV}{ql^2} = \frac{uV}{l^2\sqrt{q\alpha}} $$
This equation expresses the fact previously noted that, for small
voltages, the current _i_ is proportional to _V_.
Let
_i/I_ = ρ,
then
$$ V = \frac {\rho l^2 \sqrt {q\alpha}} {u} $$
Now the greater the value of _V_ required to obtain a given value of ρ
(supposed small compared with unity), the greater the potential required
to produce saturation.
It thus follows from the equation that:
(1) For a given intensity of radiation, the saturation P.D. increases
with the distance between the plates. In the equation, for small values
of ρ, _V_ varies as _l²_. This is found to be the case for uniform
ionization, but it only holds approximately for non-uniform ionization.
(2) For a given distance between the plates, the saturation P.D. is
greater, the greater the intensity of ionization between the plates.
This is found to be the case for the ionization produced by radio-active
substances. With a very active substance like radium, the ionization
produced is so intense that very large voltages are required to produce
approximate saturation. On the other hand, only a fraction of a volt per
cm. is necessary to produce saturation in a gas where the ionization is
very slight, for example, in the case of the natural ionization observed
in a closed vessel, where no radio-active substances are present.
Public-domain text, read in full here on John Shaqi.
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