Spinning Tops: The "Operatives' Lecture" of the British Association Meeting at Leeds, 6th September, 1890Perry, John
Science
Spinning Tops: The "Operatives' Lecture" of the British Association Meeting at Leeds, 6th September, 1890
Perry, John
Gyro compass; Gyroscopes; Tops
The explanation of our rule is easy. Here is a gyrostat (Fig. 23) something
like the earth in shape, and it is at rest. I am sorry to say that I am
compelled to support this globe in a very visible manner by gymbal rings.
If this globe were just floating in the air, if it had no tendency to fall,
my explanation would be easier to understand, and I could illustrate it
better experimentally. Observe the point P. If I move the globe slightly
about the axis A, the point P moves to Q. But suppose instead of this that
the globe and inner gymbal {51} ring had been moved about the axis B; the
point P would have moved to R. Well, suppose both those rotations took
place simultaneously. You all know that the point P would move neither to Q
nor to R, but it would move to S; P S being the diagonal of the little
parallelogram. The resultant motion then is neither about the axis O A in
space, nor about the axis O B, but it is about some such axis as O C.
To this globe I have given two rotations simultaneously. Suppose a little
being to exist on this globe which could not see the gymbals, but was able
to observe other objects in the room. It would say that the direction of
rotation is neither about O A nor about O B, but that the real axis of its
earth is some line intermediate, O C in fact.
If then a ball is suddenly struck in two different directions at the same
instant, to understand how it will spin we must first find how much spin
each blow would produce if it acted alone, and about what axis. A spin of
three turns per second about the axis O A (Fig. 24), and a spin of two
turns per second about the axis O B, really mean that the ball will spin
about the axis O C with a spin of three and a half turns per second. To
arrive at this result, I made O A, 3 feet long (any other scale of
representation would have been right) {52} and O B, 2 feet long, and I
found the diagonal O C of the parallelogram shown on the figure to be 3½
feet long.
Observe that if the rotation about the axis O A is _with_ the hands of a
watch looking from O to A, the rotation about the axis O B looking from O
to B, must also be with the hands of a watch, and the resultant rotation
about the axis O C is also in a direction with the hands of a watch looking
from O to C. Fig. 25 shows in two diagrams how necessary it is that on
looking from O along either O A or O B, the rotation should be in the same
direction as regards the hands of a watch. These constructions are well
known to all who have studied elementary mechanical principles. Obviously
if the rotation about O A is very much greater than the rotation about O B,
then the position of the new axis O C must be much nearer O A than O B.
[Illustration: FIG. 24.]
[Illustration: FIG. 25.]
Public-domain text, read in full here on John Shaqi.
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