The Gases of the Atmosphere: The History of Their DiscoveryRamsay, William
History
The Gases of the Atmosphere: The History of Their Discovery
Ramsay, William
Air; Argon; Chemistry -- History
When a gas expands into the atmosphere it may be regarded as “raising
the atmosphere” through a certain height, for the atmosphere possesses
weight, equal on the average to 1033 grams on each square centimetre
of the earth’s surface, or between 15 and 16 lbs. on each square
inch. Suppose a quantity of air, weighing 1 gram, to be enclosed in
a long cylindrical tube of one square centimetre in section. At the
usual pressure of the atmosphere on the earth’s surface, and at 0°
Centigrade, the volume of the air would be 773·3 cubic centimetres;
and, as the sectional area of the tube is 1 square centimetre, the air
would occupy 773·3 centimetres’ length of the tube. If heat be given
to this air, so that its temperature is raised from 0° to 1°, it will
expand, as Gay-Lussac showed, by 1/273rd of its volume. Now the product
of 773·3 and 1/273 is 2·83 centimetres; the level of the surface of
the air will rise in the tube through that amount. In doing so it will
perform the work of raising 1033 grams through 2·83 centimetres, or
2927 gram-centimetres. Careful measurements have shown that, in order
to do this work, heat to the amount of 0·0692 calory must be given to
the gas. But it has been found that to heat the air through one degree,
without allowing it to expand, requires 0·1683 calory; that is, the
same amount of heat which would raise a gram of air through one degree,
its volume being kept constant, will raise a gram of water through
0·1683°; or, in other words, the specific heat of air is 0·1683. But if
allowed to expand, more heat is required--an additional 0·0692 calory
must be given it; consequently its specific heat at constant pressure
is greater; it is actually the sum of these two numbers,
0·1683 + 0·0692 = 0·2375.
We have thus--
Specific heat at constant pressure 0·2375
" " " volume 0·1683
Ratio between these numbers: 0·2375/0·1683 = 1·41
This ratio is termed the ratio between the specific heats of air, and
such a ratio is represented usually by the letter =γ=.
But it is not necessary to determine both kinds of specific heat in
order to arrive at a knowledge of the value of this ratio. One plan,
adopted by Gay-Lussac and Désormes at the suggestion of Laplace,[28] is
to actually measure the fall of temperature by allowing a known volume
of gas, of which the weight can of course be deduced, to expand from
a pressure somewhat higher than that of the atmosphere to atmospheric
pressure. It is true that heat will rapidly flow in through the walls
of the vessel; but by choosing a sufficiently large vessel, and
surrounding its walls with badly-conducting material, the entry of heat
will be so slow that it may, for practical purposes, be neglected. The
number for this ratio, actually found by Gay-Lussac and Welters for
air, was 1·376; but subsequent and more accurate experiments have given
as a result 1·405, which is almost identical with that calculated above.
Public-domain text, read in full here on John Shaqi.
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