As at the end of the preceding calculation the results are expressed in the table following in terms of oxygen atoms obtained from each molecule of potassium permanganate [KMnO₄] reduced. Thus an equivalent of one atom of oxygen from one molecule of potassium permanganate would equal 15.96/157.67 of the weight of potassium permanganate used in the experiment. This weight divided by the weight of one cubic centimetre of oxygen gives the number of cubic centimetres of oxygen at normal, equivalent to one atom of oxygen from one molecule of potassium permanganate. The results obtained are tabulated as follows: Three-hour determinations. -------------------+-------------------------+---------------------- Flask I | Flask II | Flask III -------------------+-------------------------+---------------------- MnO₂ N/10 HNO₃| KMnO₄ N/10 HNO₃ | KMnO₄ N/10 HNO₃ [150 m.g.] No. of | 20 c.c. = No. of | 20 c.c. = No. of molecules | 112.48 m.g. molecules | 112.48 m.g. molecules -------------------+-------------------------+---------------------- 1 0.00 2 0.13 1 1.495 3 2 0.00 ” ? 1 1.493 ” 3 ” 0.13 3 1.532* ” 4 0.00 ” 0.21 ” 1.466 ” 5 0.03 ” 0.10 ” 1.467 ” 6 0.02 ” 0.25 ” ” 7 0.06 ” 0.08 ” 1.526* ” 8 0.04 ” 0.15 ” 1.527 ” 9 0.04 ” 0.11 ” 1.504 ” 10 ” 0.20 ” 1.504 ” 11 0.03 ” 0.14 ” 1.516 ” 12 0.00 ” 0.18 ” 1.524 ” 13 0.03 ” 0.25 ” 1.559* ” 14 0.05 ” 0.26 ” 1.574 ” 15 0.02 1 0.32 2 1.552 2 16 0.03 ” 0.31 ” 1.583? ” 17 0.04 ” 0.31 ” 1.512 ” 18 0.01 ” 0.32 ” 1.466 ” 19 0.00 ” 0.18 ” 1.412 ” 20 0.01 ” 0.36 ” 1.411 ” 21 0.06 ” 0.22 ” 1.402 ” 22 0.00 ” 0.30 ” 1.495* ” 23 2 0.08 3 1.469 3 [5]Fifty minute determinations