Waves and ripples in water, air, and æther : $b Being a course of Christmas lectures delivered at the Royal Institution of Great BritainFleming, J. A. (John Ambrose), Sir
Science
Waves and ripples in water, air, and æther : $b Being a course of Christmas lectures delivered at the Royal Institution of Great Britain
Fleming, J. A. (John Ambrose), Sir
Electric waves; Sound; Waves
We must first transform a speed of 27 miles per hour into its
equivalent in feet per second. Since one mile is 5280 feet, 27 miles
per hour is equal to 2376 feet per minute. Accordingly, it is easy
to see that the wave-frequency must be 7·92, or nearly 8, because
7·92 times 300 is 2376. The answer to the question is, then, that the
floating object will rise and fall eight times a minute. This rule may
be embodied in a compact form, which it is desirable to hold firmly in
the memory, viz.—
_Wave-velocity_ = _wave-length_ × _wave-frequency_.
This relation, which we shall have frequent occasion to recall, may be
stated in another manner. We call the _period_ of a wave the time taken
to make one complete movement. The periodic time is therefore inversely
proportional to the frequency. Hence we can say that the _wave-length_,
divided by the _periodic time_, gives us the _wave-velocity_.
In the case of water waves and ripples, the wave-velocity is determined
by the wave-length. This is not the case, as we shall see, with waves
in air or waves in æther. In these latter cases, as far as we know,
waves of all wave-lengths travel at the same rate. Long sea waves,
however, on deep water travel faster than short ones.
A formal and exact proof of the law connecting speed and wave-length
for deep-sea waves requires mathematical reasoning of an advanced
character; but its results may be expressed in a very simple statement,
by saying that, in the case of waves on deep water, the speed with
which the waves travel, reckoned in miles per hour, is equal to the
square root of 2¹⁄₄ times the wave-length measured in feet. Thus, for
instance, if we notice waves on a deep sea which are 100 feet from
crest to crest, then the speed with which those waves are travelling,
reckoned in miles per hour, is a number obtained by taking the square
root of 2¹⁄₄ times 100, viz. 225. Since 15 is the square root of 225
(because 15 times 15 is 225), the speed of these waves is therefore 15
miles an hour.
In the same way it can be found that Atlantic waves 300 feet long would
travel at the rate of 26 miles an hour, or as fast as a slow railway
train, and much faster than any ordinary ship.[1]
The above rule for the speed of deep-sea waves, viz. _wave-velocity_ =
_square root of 2¹⁄₄ times the wave-length_, combined with the general
rule, _wave-velocity_ = _wave-length multiplied by frequency_, provides
us with a useful practical method of finding the speed of deep-sea
waves which are passing any fixed point. Suppose that a good way out
at sea there is a fixed buoy or rock, and we notice waves racing past
it, and desire to know their speed, we may do it as follows: Count
the number of waves which pass the fixed point per minute, and divide
the number into 198; the quotient is the speed of the waves in miles
per hour. Thus, if ten waves per minute race past a fixed buoy, their
velocity is very nearly 20 miles an hour.[2]
Public-domain text, read in full here on John Shaqi.
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