The English works of Thomas Hobbes of Malmesbury, Volume 01 (of 11)
Thomas Hobbes · en
[Sidenote: How from the description of deficient figures in a
parallelogram, any number of mean proportionals may be found
out between two given strait lines.]
14. If these deficient figures, which I have described in a
parallelogram, were capable of exact description, then any number of
mean proportionals might be found out between two strait lines given.
For example, in the parallelogram A B C D, (in figure 8) let the
three-sided figure of two means be described (which many call a _cubical
parabola_); and let R and S be two given strait lines; between which, if
it be required to find two mean proportionals, it may be done thus. Let
it be as R to S, so B C to B F; and let F E be drawn parallel to B A,
and cut the crooked line in E; then through E let G H be drawn parallel
and equal to the strait line A D, and cut the diagonal B D in I; for
thus we have G I the greatest of two means between G H and G E, as
appears by the description of the figure in article 4. Wherefore, if it
be as G H to G I, so R to another line, T, that T will be the greatest
of two means between R and S. And therefore if it be again as R to T, so
T to another line, X, that will be done which was required.
In the same manner, four mean proportionals may be found out, by the
description of a three-sided figure of four means; and so any other
number of means, &c.
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[Illustration:
_Vol. 1. Lat. & Eng._
C. XVII.
_Fig. 1-8_
]
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CHAPTER XVIII.
OF THE EQUATION OF STRAIT LINES WITH THE
CROOKED LINES OF PARABOLAS AND OTHER
FIGURES MADE IN IMITATION OF PARABOLAS.
1. To find the strait line equal to the crooked line of a
semiparabola.—2. To find a strait line equal to the crooked line of
the first semiparabolaster, or to the crooked line of any other of
the deficient figures of the table of the 3d article of the
precedent chapter.
[Sidenote: To find a strait line equal to the crooked line of a
semiparabola.]
1. A parabola being given, to find a strait line equal to the crooked
line of the semiparabola.
Let the parabolical line given be A B C (in figure 1), and the diameter
found be A D, and the base drawn D C; and the parallelogram A D C E
being completed, draw the strait line A C. Then dividing A D into two
equal parts in F, draw F H equal and parallel to D C, cutting A C in K,
and the parabolical line in O; and between F H and F O take a mean
proportional F P, and draw A O, A P and P C. I say that the two lines A
P and P C, taken together as one line, are equal to the parabolical line
A B O C.