_Field of Eyepiece._—Observers often require to know the diameter of
the fields of their eyepieces. Those engaged in sweeping up comets,
nebulæ, or other objects requiring large fields and low powers, find
it quite important to have this information. They may acquire it for
themselves by simple methods. A planet, or star such as δ Orionis, η
or γ Virginis, or η Aquilæ, close to the equator, should be allowed to
run exactly through the centre of the field, and the interval occupied
in its complete transit from ingress to egress noted several times. The
mean result in min. and sec. of time must then be multiplied by 15,
and this will represent the diameter required in min. and sec. of arc
on the equator. A planet or star near the meridian is the best for the
purpose. If the object occupies 1 min. 27 sec. of time in passing from
the E. to the W. limit of the field, then 87 sec. × 15 = 1305″, or 21′
45″. A more accurate method of deriving the angle subtended by the
field is to let a star, say Regulus, pass through the centre, and fix
the time which lapses in its entire passage by a sidereal clock; then
the interval so found × 15 × cosine of the declination of Regulus will
indicate the diameter of the field. Suppose for instance, that the star
named occupies 2 min. 14 sec. = 134 sec. in its passage right across
the whole and central part of the field: then
134 log 2·127105
15 log 1·176091
Dec. of Regulus 12° 30′ log cos 9·989581
————————
1962″ log 3·292777
so that the diameter of the field of the eyepiece must be 32′ 42″,
nearly corresponding with the diameter of the Moon.
Public-domain text, read in full here on John Shaqi.
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